A right-angled triangle has legs \( 5 \) cm and \( 12 \) cm. Find the hypotenuse.
\( \sqrt{25 + 144} = \sqrt{169} = 13 \) cm.
10 exam-style questions on Pythagoras’ theorem, right-angled trigonometry and exact values.
A right-angled triangle has legs \( 5 \) cm and \( 12 \) cm. Find the hypotenuse.
\( \sqrt{25 + 144} = \sqrt{169} = 13 \) cm.
In a right-angled triangle, opposite \( = 4 \), adjacent \( = 3 \). Find \( \sin \theta \) and \( \cos \theta \).
Hypotenuse \( = 5 \). \( \sin \theta = \dfrac{4}{5} \), \( \cos \theta = \dfrac{3}{5} \).
Write down the exact value of \( \sin 30^\circ \) and \( \tan 45^\circ \).
\( \sin 30^\circ = \dfrac{1}{2} \), \( \tan 45^\circ = 1 \).
A ladder \( 5 \) m long leans against a wall. The foot is \( 1.5 \) m from the wall. How far up the wall does it reach?
\( h = \sqrt{25 - 2.25} = \sqrt{22.75} \approx 4.77 \) m.
In a right-angled triangle, the angle is \( 35^\circ \) and the adjacent side is \( 8 \) cm. Find the opposite side to 1 d.p.
\( \tan 35^\circ = \dfrac{\text{opp}}{8} \) ⇒ opp \( = 8 \tan 35^\circ \approx 5.6 \) cm.
Find the size of angle \( \theta \) if \( \sin \theta = 0.6 \) and \( \theta \) is acute. Give your answer to the nearest degree.
\( \theta = \sin^{-1}(0.6) \approx 37^\circ \).
A triangle has sides \( 7 \) cm, \( 24 \) cm and \( 25 \) cm. Is it right-angled? Justify.
\( 7^2 + 24^2 = 49 + 576 = 625 = 25^2 \). Yes, by converse of Pythagoras.
An isosceles right-angled triangle has equal sides of length \( 6 \) cm. Find the exact length of the hypotenuse.
\( \sqrt{36 + 36} = \sqrt{72} = 6\sqrt{2} \) cm.
From a point \( 40 \) m from the base of a building, the angle of elevation to the top is \( 28^\circ \). Find the height of the building to 1 d.p.
\( h = 40 \tan 28^\circ \approx 21.3 \) m.
Write down the exact value of \( \cos 60^\circ \) and use it to find the exact length of the adjacent side when the hypotenuse is \( 10 \) cm and the angle is \( 60^\circ \).
\( \cos 60^\circ = \dfrac{1}{2} \). Adjacent \( = 10 \times \dfrac{1}{2} = 5 \) cm.